Claudio scrive: Espressione con frazioni algebriche

Oggetto: Espressione con frazioni algebriche

Corpo del messaggio:
[[(a^2-2a+1)/a^2- [(a^2)/(a^2+2a+1)]]: [2-1/a-1/(a+1)]^2
risultato1/(1-2a^2)

$\left[ \left[ \frac {a^2-2a+1}{a^2}- \left( \frac {a^2}{a^2+2a+1}\right) \right] \right] : \left[ 2- \frac 1 a - \frac {1}{(a+1)^2} \right]^2=$

$\left[ \frac {(a^2-2a+1)(a^2+2a+1)-a^4}{a^2(a+1)^2} \right] : \left[ \frac {2a(a+1)-(a+1)-a}{a(a+1)} \right]^2=$

$\left[ \frac {a^4+2a^3+a^2-2a^3-4a^2-2a+a^2+2a+1-a^4}{a^2(a+1)^2} \right] : \left[ \frac {\left(2a^2+2a-a-1-a\right)^2}{a^2(a+1)^2} \right]=$

$\left[ \frac {-2a^2+1}{a^2(a+1)^2} \right] : \left[ \frac {(2a^2-1)^2}{a^2(a+1)^2} \right]=$

$\frac {-(2a^2-1)}{a^2(a+1)^2} \cdot \frac {a^2(a+1)^2}{(2a^2-1)^2}=$

$-\frac {1}{2a^2-1}=\frac {1}{1-2a^2}.$

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